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Compare the Triplets (Hacker Rank)

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from  to  for three categories: problem clarity, originality, and difficulty.

We define the rating for Alice's challenge to be the triplet , and the rating for Bob's challenge to be the triplet .

Your task is to find their comparison points by comparing  with ,  with , and  with .

If , then Alice is awarded  point.
If , then Bob is awarded  point.
If , then neither person receives a point.
Comparison points is the total points a person earned.

Given  and , can you compare the two challenges and print their respective comparison points?
#!/bin/python3

import sys

def solve(a0, a1, a2, b0, b1, b2):
    a = (1 if a0 > b0 else 0) + (1 if a1 > b1 else 0) + (1 if a2 > b2 else 0)
    b = (1 if a0 < b0 else 0) + (1 if a1 < b1 else 0) + (1 if a2 < b2 else 0)

    return (a,b)


a0, a1, a2 = input().strip().split(' ')
a0, a1, a2 = [int(a0), int(a1), int(a2)]
b0, b1, b2 = input().strip().split(' ')
b0, b1, b2 = [int(b0), int(b1), int(b2)]
result = solve(a0, a1, a2, b0, b1, b2)
print (" ".join(map(str, result)))


Wrong answer 였지만 zip함수 사용
#!/bin/python3

import sys

def solve(a0, a1, a2, b0, b1, b2):
  result = []
      a_arr = [a0, a1, a2]
      b_arr = [b0, b1, b2]

      for a, b in zip(a_arr, b_arr):
          if a > b or a < b:
              result.append(1)

  return result

a0, a1, a2 = input().strip().split(' ')
a0, a1, a2 = [int(a0), int(a1), int(a2)]
b0, b1, b2 = input().strip().split(' ')
b0, b1, b2 = [int(b0), int(b1), int(b2)]
result = solve(a0, a1, a2, b0, b1, b2)
print (" ".join(map(str, result)))
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